Termination w.r.t. Q proof of TRS/TRCSREx1_2_Luc02c

Termination w.r.t. Q of the following Term Rewriting System could be proven:

Q restricted rewrite system:
The TRS R consists of the following rules:

2nd(cons(X, n__cons(Y, Z))) → activate(Y)
from(X) → cons(X, n__from(n__s(X)))
cons(X1, X2) → n__cons(X1, X2)
from(X) → n__from(X)
s(X) → n__s(X)
activate(n__cons(X1, X2)) → cons(activate(X1), X2)
activate(n__from(X)) → from(activate(X))
activate(n__s(X)) → s(activate(X))
activate(X) → X

Q is empty.

↳ QTRS

  ↳ DirectTerminationProof

Q restricted rewrite system:
The TRS R consists of the following rules:

2nd(cons(X, n__cons(Y, Z))) → activate(Y)
from(X) → cons(X, n__from(n__s(X)))
cons(X1, X2) → n__cons(X1, X2)
from(X) → n__from(X)
s(X) → n__s(X)
activate(n__cons(X1, X2)) → cons(activate(X1), X2)
activate(n__from(X)) → from(activate(X))
activate(n__s(X)) → s(activate(X))
activate(X) → X

Q is empty.

We use [23] with the following order to prove termination.

Recursive path order with status [2].
Precedence:

2nd₁ > activate₁ > from₁ > cons₂ > n_{_cons₂}
2nd₁ > activate₁ > from₁ > n_{_from₁} > n_{_cons₂}
2nd₁ > activate₁ > from₁ > n_{_s₁} > n_{_cons₂}
2nd₁ > activate₁ > s₁ > n_{_s₁} > n_{_cons₂}

Status:

from₁: multiset
n_{_from₁}: multiset
n_{_s₁}: multiset
s₁: multiset
cons₂: multiset
activate₁: [1]
n_{_cons₂}: multiset
2nd₁: multiset